韦达定理推导过程视频（韦达定理推导过程）
导读 ax^2+bx+c=0 两边同除以a x^2 +b/a x +c/a = 0 配方 (x+ b/(2a) )^2 +c/a -b^2/(4a^2) = 0 (x+ b/(2a) )^2 =b^2/(4a^...
ax^2+bx+c=0 两边同除以a x^2 +b/a x +c/a = 0 配方 (x+ b/(2a) )^2 +c/a -b^2/(4a^2) = 0 (x+ b/(2a) )^2 =b^2/(4a^2) - c/a 开方 x+b/(2a) = +或- √[b^2/(4a^2) - c/a ] y1 = -b/(2a) + √[b^2/(4a^2) - c/a ] = [-b + √(b^2-4ac)] /(2a) y2 = -b/(2a) - √[b^2/(4a^2) - c/a ] = [-b - √(b^2-4ac)] /(2a)。
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